If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
(4*x-3)^2 = 0
(4*x-3)^2 = 0
(4*x-3)^2 = 0
4*x-3 = 0 // + 3
4*x = 3 // : 4
x = 3/4
x in (-oo:3/4) U (3/4:+oo)
y = 1/((4*x-3)^2) // - 1/((4*x-3)^2)
y-(1/((4*x-3)^2)) = 0
y-(4*x-3)^-2 = 0
y-1/((4*x-3)^2) = 0
(y*(4*x-3)^2)/((4*x-3)^2)-1/((4*x-3)^2) = 0
y*(4*x-3)^2-1 = 0
16*x^2*y-24*x*y+9*y-1 = 0
(16*x^2*y-24*x*y+9*y-1)/((4*x-3)^2) = 0
(16*x^2*y-24*x*y+9*y-1)/((4*x-3)^2) = 0 // * (4*x-3)^2
16*x^2*y-24*x*y+9*y-1 = 0
16*x^2*y-24*x*y+9*y-1 = 0
DELTA = (-24*y)^2-(4*16*y*(9*y-1))
DELTA = 576*y^2-64*y*(9*y-1)
576*y^2-64*y*(9*y-1) = 0
576*y^2-64*y*(9*y-1) = 0
64*y = 0
64*y = 0
64*y = 0 // : 64
y = 0
DELTA = 0 <=> t_3 = 0
x = (-(-24*y))/(2*16*y) i y = 0
x = 3/4 i y = 0
( x = ((576*y^2-64*y*(9*y-1))^(1/2)-(-24*y))/(2*16*y) or x = (-(576*y^2-64*y*(9*y-1))^(1/2)-(-24*y))/(2*16*y) ) i y > 0
( x = ((576*y^2-64*y*(9*y-1))^(1/2)+24*y)/(32*y) or x = (24*y-(576*y^2-64*y*(9*y-1))^(1/2))/(32*y) ) i y > 0
y+0 > 0
y > 0
y+0 > 0 // - 0
y > 0
x in { 3/4 i y -> {0}}
x in { ((576*y^2-64*y*(9*y-1))^(1/2)+24*y)/(32*y), (24*y-(576*y^2-64*y*(9*y-1))^(1/2))/(32*y) }
| 8/2*5*1/5= | | 2x+100=500+500 | | 6x-12-5=3 | | -5[3+5(-9+5)]+15= | | -5(x+1)+3(3x-4)=3(x-6)+11 | | X^2+x+2y-10=0 | | h=25t-5t^2+0.2 | | -2y=x+5 | | 2(y-2)=5(y+2)-2 | | Tan27=7/x | | 7x=-7+35 | | 7x-35=7 | | 8=3x+1x | | 7(x+2)-2=2x+5(3+x) | | (y^2+14y+54)=0 | | Y+6+7x=0 | | (5y^2-7y-6)=0 | | 5x=-12+1 | | -8-9m=-8m | | (3x^2+8x+4)=0 | | 0=181-16t^2 | | -20x^7-4x^6=0 | | -6+5v=3v | | 6(d+9)= | | -8f=-7f+4 | | 7w=9+6w | | y=(5x^5)(ln(1/x) | | x*1.2=95 | | (w^2-6w+15)=0 | | 7-9q=10q | | x/2x-5 | | 1/5k=4 |